Factor 26r3s + 52r5 – 39r2s4. What is the resulting expression? 13(2r3s + 4r5 – 3r2s4) 13r2s(2r + 4r3 – 3s3) 13r2(2rs + 4r3 – 3s4) 13r2(26r3s + 52r5 – 39r2s4)

Respuesta :

Answer:

The correct option is option (c).

Step-by-step explanation:

Factor: The smallest divisor of function is the factors of the function.

26r³s = 13×2×r×r×r×s

52r⁵= 13×2×2×r×r×r×r×r

39r²s⁴ = 13×3×r×r×s×s×s×s

The common factors are = 13×r×r =13r²

Therefore  

26r³s+52r⁵-39r²s⁴

=( 13×2×r×r×r×s)+(13×2×2×r×r×r×r×r)-(13×3×r×r×s×s×s×s)

=13r²(2×r×s+2×2×r×r×r-3×s×s×s×s)

=13r²(2rs+4r³-3s⁴ )

∴26r³s+52r⁵-39r²s⁴ =13r²(2rs+4r³-3s⁴ )

The factorization of 26r³s + 52r^5 – 39r²s⁴ is 13r²(2rs + 4r³ - 3s⁴)

How to factorise

Given:

26r³s + 52r^5 – 39r²s⁴

factorize

= 13r²(2rs + 4r³ - 3s⁴)

check all that applies

  • 13(2r³s + 4r^5 – 3r²s⁴)

Not applicable

  • 13r²s(2r + 4r³ – 3s³)

Not applicable

  • 13r²(2rs + 4r³ – 3s⁴)

Applicable

  • 13r²(26r³s + 52r^5 – 39r²s⁴)

Not applicable

Learn more about factorization:

https://brainly.com/question/11579257

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE