The volume of the cone shown is 6 cubic inches. What is the height of a cone with the same base diameter but a volume of only 3 cubic inches? Please tell me the exact answer.

The volume of the cone shown is 6 cubic inches What is the height of a cone with the same base diameter but a volume of only 3 cubic inches Please tell me the e class=

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Answer:

3 cubic inches

Step-by-step explanation:

[tex]volume \: of \: cone = \frac{1}{3} (base \: area)(height)[/tex]

Volume of cone shown= 6 cubic inches

Let the base diameter be 2x.

Therefore, radius= x

[tex] \frac{1}{3} (\pi {x}^{2})(6) = 6 \\ \frac{1}{3} \pi {x}^{2} = 1 \: \: \: \: \: ( \div 6 \: throughout)[/tex]

Since the base diameter is the same, the base area is the same.

Using the formula, volume of cone[tex] = \frac{1}{3} (\pi {x}^{2}) (3)[/tex]

Subst. the known value of [tex] \frac{1}{3} \pi {x}^{2} [/tex] into the equation.

Thus, volume of cone= 1(3)= 3 cubic inches

Answer:

3 cubic inches

Step-by-step explanation:

[volume of the cone]=(1/3)*area of the base*height

h-----> height  

AB-----> area of the base

so

[volume of the original cone]=(1/3)*AB*h

volume=6 in³

(1/3)*AB*h=6--------> h=18/AB

For a cone with the same base diameter but a volume of only 3 cubic inches

(1/3)*AB*h=3 in³-------> h=9*AB

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