The volume of the cone shown is 6 cubic inches. What is the height of a cone with the same base diameter but a volume of only 3 cubic inches? Please tell me the exact answer.

Answer:
3 cubic inches
Step-by-step explanation:
[tex]volume \: of \: cone = \frac{1}{3} (base \: area)(height)[/tex]
Volume of cone shown= 6 cubic inches
Let the base diameter be 2x.
Therefore, radius= x
[tex] \frac{1}{3} (\pi {x}^{2})(6) = 6 \\ \frac{1}{3} \pi {x}^{2} = 1 \: \: \: \: \: ( \div 6 \: throughout)[/tex]
Since the base diameter is the same, the base area is the same.
Using the formula, volume of cone[tex] = \frac{1}{3} (\pi {x}^{2}) (3)[/tex]
Subst. the known value of [tex] \frac{1}{3} \pi {x}^{2} [/tex] into the equation.
Thus, volume of cone= 1(3)= 3 cubic inches
Answer:
3 cubic inches
Step-by-step explanation:
[volume of the cone]=(1/3)*area of the base*height
h-----> height
AB-----> area of the base
so
[volume of the original cone]=(1/3)*AB*h
volume=6 in³
(1/3)*AB*h=6--------> h=18/AB
For a cone with the same base diameter but a volume of only 3 cubic inches
(1/3)*AB*h=3 in³-------> h=9*AB