Respuesta :
Answer: pH of resulting solution will be 13
Explanation:
pH is the measure of acidity or alkalinity of a solution.
Moles of [tex]H^+[/tex] ion = [tex]Molarity\times {\text {Volume in L}}=1M\times 0.01L=0.01mol[/tex]
Moles of [tex]OH^-[/tex] ion = [tex]Molarity\times {\text {Volume in L}}=1.2M\times 0.01L=0.012mol[/tex]
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
For neutralization:
1 mole of [tex]H^+[/tex] ion will react with 1 mole of [tex]OH^-[/tex] ion
0.01 mol of [tex]H^+[/tex] ion will react with =[tex]\frac{1}{1}\times 0.01mole[/tex] of [tex]OH^-[/tex] ion
Thus (0.012-0.01)= 0.002 moles of [tex]OH^-[/tex] are left in 20 ml or 0.02 L of solution.
[tex][OH^-]=\frac{0.002}{0.02L}=0.1M[/tex]
[tex]pOH=-log[OH^-][/tex]
[tex]pOH=-log[0.1]=1[/tex]
[tex]pH+pOH=14[/tex]
[tex]pH=14-1=13[/tex]
Thus the pH of resulting solution will be 13
The mixing of the two components is known as a solution. The components are as follow:-
- Solute
- Solvent
The Ph of the solution will be 13. The solution is as follows:-
All the data are given in question, therefore the molarity and the molality of the solution are 0.01M and 0.012m.
[tex]HCL + NaOH ----->Nacl + H_2O[/tex]
When acid reacts with the base it makes salt and this process is known as neutralization. The effects of acid neutralized by the base.
Hence, the amount of H+ and OH- will be the same in the solution.
After solving the equation.
[tex][OH-] = \frac{0.02}{0.012} = 0.1M[/tex]
The PH of the solution is
[tex]pH + pOH = 14\\\\Ph= 14- 1 =13[/tex]
Hence, the ph of the solution is 13
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https://brainly.com/question/18024346
