Respuesta :
final speed of the 3.0 kg cart is 2.67 m/s .
Step-by-step explanation:
Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
[tex]m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)[/tex]
⇒ [tex]m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)[/tex]
⇒ [tex]2(5)+3(0) =2(1)+3(v_4)[/tex]
⇒ [tex]10 =2+3(v_4)[/tex]
⇒ [tex]3(v_4) = 8[/tex]
⇒ [tex](v_4) = \frac{8}{3}[/tex]
⇒ [tex](v_4) = 2.67[/tex]
Therefore, final speed of the 3.0 kg cart is 2.67 m/s .
