Answer:
[tex] \sqrt{29} units[/tex]
Step-by-step explanation:
The magnitude of the vector with the initial point (1,3) and terminal point (-1,-2) can be calculated using;
[tex] | \vec v| = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} [/tex]
We substitute the coordinates of the initial and terminal points to get:
[tex] | \vec v| = \sqrt{( - 1-1)^2 + ( - 2-3)^2} [/tex]
We simplify to get:
[tex]| \vec v| = \sqrt{( -2)^2 + ( - 5)^2} [/tex]
[tex]| \vec v| = \sqrt{4 + 25} [/tex]
[tex]| \vec v| = \sqrt{29} [/tex]
[tex]| \vec v| = 5.39 \: units[/tex]
