value of y which satisfies equation [tex]3y+8=7y+11[/tex] is [tex]y= \frac{-3}{4}[/tex] .
Step-by-step explanation:
We have , 3y+8=7y+11 . We need to find which value of y satisfies this equation 3y+8=7y+11 :
[tex]3y+8=7y+11[/tex]
⇒ [tex]3y+8=7y+11[/tex]
⇒ [tex](3y+8)-3y=(7y+11)-3y[/tex]
⇒ [tex]8=4y+11[/tex]
⇒ [tex]4y+11 = 8[/tex]
⇒ [tex](4y+11)-11 = 8-11[/tex]
⇒ [tex]4y= -3[/tex]
⇒ [tex]\frac{4}{4}y= \frac{-3}{4}[/tex]
⇒ [tex]y= \frac{-3}{4}[/tex]
Therefore, value of y which satisfies equation [tex]3y+8=7y+11[/tex] is [tex]y= \frac{-3}{4}[/tex] .
