Answer:
It would be significant
Step-by-step explanation:
Population proportion of consumers who recognize the company name = 68% = 0.68
If 634 consumers out of the 800 randomly selected consumers recognize the company name, sample proportion = 634/800 = 0.7925.
It is significant to get 634 because the sample proportion of consumers who recognize the company name is greater than the population proportion.
Given Information:
Probability = p = 68% = 0.68
Population = n = 800
Answer:
it would not be significant to get 634 consumers who might recognize the name of Dull Computer Company.
Step-by-step explanation:
We can check whether it would be significant to get 635 consumers who recognize the Dull Computer Company by finding out the mean and standard deviation.
mean = μ = np
μ = 800*0.68
μ = 544
standard deviation = σ = √np(1-p)
σ = √800*0.68(1-0.68)
σ = 13.2 ≈ 13
we know that 99% of data fall within 3 standard deviations from the mean
μ ± 3σ = 544+3*13, 544-2*13
μ ± 3σ = 544+39, 544-39
μ ± 3σ = 583, 505
So we can say with 99% confidence that the number of consumers who can recognize the name of Dull Computer Company will be from 505 to 583 and since 583 < 634 we can conclude that it would not be significant to get 634 consumers who might recognize the name of Dull Computer Company.
