Answer:
0.235
Explanation:
Given
Distance between A and B = 0.10
Distance between B and C = 0.15
Distance between A and C = 0.25
The probability of double crossovers (DCO) are determined by the product of two single crossovers;
Therefore, the probability of a DCO = 0.10 * 0.15
= 0.015
= 1.5%
As the failure to detect a recombination is in DCO, the loci at 25cM will only show recombination at a frequency of:
25 - 1.5
= 23.5%
Hence, the probability that the trihybrid ABC/abc will produce any kind of recombinant gamete = 23.5% = 0.235
The probability that the trihybrid ABC/ABC will produce any kind of recombinant gamete is 0.235.
Since
Distance between A and B = 0.10
Distance between B and C = 0.15
Distance between A and C = 0.25
Now
the probability of a DCO = 0.10 * 0.15
= 0.015
= 1.5%
So, here the probability should be
= 25 - 1.5
= 23.5%
hence, The probability that the trihybrid ABC/ABC will produce any kind of recombinant gamete is 0.235.
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