Answer:
mean average = 2542.5 mg
1330 mg
Explanation:
The patient's average daily intake of sodium for those 4 days can be calculated by taking the mean average of the sample amounts given over the number of the total days.
[tex]mean average = \frac{2150+3005+2700+2315}{4}[/tex]
[tex]mean average = \frac{10170}{4}[/tex]
mean average = 2542.5 mg
Therefore the patient's average daily intake of sodium for those 4 days = 2542.5 mg
What is the patient’s average daily intake of sodium for those 4 days?
What would his 5th day sodium intake need to be to drop him below an average of 2300 mg
given that mean average = 2300; we can also determine the fifth day sodium intake as follows:
[tex]mean average = \frac{2150+3005+2700+2315+y}{5}\\2300 = \frac{2150+3005+2700+2315+y}{5}[/tex]
[tex]2300*5 =2150+3005+2700+2315+y[/tex]
[tex]11500 = 10170 +y[/tex]
[tex]11500-10170 =y[/tex]
y = 1330 mg
Hence, his sodium intake for the fifth day will be 1330 in order to drop him below an average of 2300 mg
