Answer:
maximum height: 196
height of ball after 2 seconds: 160
ball reaches ground: 7 seconds
Explanation:
height of ball after 2 seconds:
s(t)=-16t^2+112t
s(2)= -16(2)^2 + 112(2)
=-64+224
=160
max height enter in vertex formula: (-b\2a)
-(112)/2(-16)
=112/32
=3.5 (x-value) substitute in original equation and thats the maximum height.
s(3.5)= -16(3.5)^2+ 112(3.5)
=196
ball reaches gound:
need to find when s(t)=0; (use the quadratic formula or factor)
-16t^2 + 112t =0
-16t (t-7) =0
-16t =0 or t-7 =0
t =0 t =7
