Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001 [tex]m^{3}[/tex]
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13 [tex]\frac{J}{kg k}[/tex]
From ideal gas equation P V = m RT
⇒ P = [tex]\frac{m R T}{V}[/tex]
Put all the values in above formula we get
⇒ P = [tex]\frac{0.00115}{0.001}[/tex] × 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
