Answer:
630 W bulb has lower resistance than 315 W bulb
Explanation:
The resistance of the bulb can be found using the operating voltage of the bulbs and their wattage.
As we know from Ohm's law
V = IR
I = V/R
Also power is given by
P = VI
P = V*(V/R)
P = V²/R
R = V²/P
For Bulb 1:
R = 120²/630
R = 22.85 Ω
For Bulb 2:
R = 120²/315
R = 45.71 Ω
Therefore, the bulb with a higher wattage of 630 W has lower resistance than the bulb with a lower wattage of 315 W.
