Answer:
The molarity of a MnO4- solution
= 0.0342 M
Explanation:
Equation of reaction:
5Fe2 (aq) MnO4-(aq) 8H (aq) ---> 5Fe3 (aq) Mn2 (aq) 4H2O(l)
This is an example of redox titration.
Using titration formula:
CAVA/CBVA = NA/NB
where CA is the molarity of Fe2+ = (0.134 M)
CB is the molarity of MnO4- = (?????)
VA is the volume of Fe2+ = (30mL)
VB is the volume of MnO4- =(23.5mL)
NA is the numeric coefficient of Fe2+ in the equation of reaction = ( 5 )
NB is the numeric coefficient of MnO4- in the equation of reaction =(1)
Substituting the values into the formula;
0.134×30/CB×23.5 = 5/1
Therefore CB = 0.134×30/23.5×5
= 0.0342 M
