Answer:
[tex]u = 2.5 \ m/s[/tex]
Explanation:
Given data:
Height, [tex]h = 210 \ m[/tex]
Time, [tex]t = 6.3 \ s[/tex]
Let the initial velocity of the object be u.
From the kinematic equation,
[tex]h = ut + \frac{1}{2}gt^{2}[/tex]
[tex]210 = u \times 6.3 + 0.5 \times 9.80 \times (6.3)^{2}[/tex]
[tex]\Rightarrow \ u = 2.46 \ m/s[/tex]
[tex]u = 2.5 \ m/s[/tex] (rounding to tenth place)
