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A transformer coil has 20 turns on one end and 200 turns on the other end. An emf of 300 V comes into the 20 turn end. How much emf comes out of the 200 turn end of the transformer? (1 point) 3000 V 6000 V 13000 V 9000 V

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MechEngineer

Answer:

3000 V

Explanation:

As for transformer, the following formula can be applied to calculate the ratios:

[tex]\frac{V_1}{V_2} = \frac{S_1}{S_2}[/tex]

where S1 = 20 turns, S2 = 200 turns, V1 = 300 V are the number of coils and voltage across the 1st and 2nd end, respectively

[tex]V_2 = V_1\frac{S_2}{S_1} = 300*\frac{200}{20} = 300*10 = 3000 V[/tex]

asuwafoh

Answer:

3000 V

Explanation:

Using transformer equation,

Vs/Vp = Ns/Np...................... Equation 1

Where Vs = Voltage applied to the secondary coil, Vp = voltage applied to the primary coil, Ns = number of turns in the secondary coil, Np = number of coil in the primary coil.

make Vs the subject of the equation

Vs = NsVp/Np.............. Equation 2

Given:  Vp = 300 V, Ns = 200 turns, Np = 20 turns

Substitute into equation 2

Vs = 300(200)/20

Vs = 3000 V.

Hence the emf that comes out of the 200 turns end of the transformer = 3000 V

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