Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
[tex]v_{1}=\frac{(M+m)u-mv}{M}[/tex]
Substitute the suitable values in the above equation.
[tex]v_{1}=\frac{(62.2+0.145)2.66-0.145\times39.3}{62.2}[/tex]
v₁ = 2.57 m/s
