Answer:
[tex]v\approx 16.956\,\frac{m}{s}[/tex]
Explanation:
The motion of the vehicule on a highway curve can be modelled by the following equation of equilibrium:
[tex]\Sigma F = f = m\cdot \frac{v^{2}}{R}[/tex]
The maximum speed is:
[tex]v = \sqrt{\frac{f\cdot R}{m} }[/tex]
[tex]v = \sqrt{\frac{(7500\,N)\cdot (46\,m)}{1200\,kg} }[/tex]
[tex]v\approx 16.956\,\frac{m}{s}[/tex]
