Answer:
= + 2.27m
Explanation:
[tex]y_c_m = \frac{m_1y_1 + m_2y_2 + m_3y_3 + m_4y_4}{y_1 +y_2+ y_3 +y_4}[/tex]
Given that,
mass (1) 1.96 kg object is at +2.90 m,
mass(2) 2.98 kgobject is at +2.46 m
mass(3) 2.60 kg object is at the origin
mass(4) 3.99 kg object is at -0.503 m
[tex]y = \frac{(1.96 \times 2.90)+ (2.98 \times2.46) + (2.60 \times 0)- (3.99\times0.503) }{2.90 + 2.46 + 0 - 0.503}[/tex]
[tex]= \frac{11.00783}{4.857}[/tex]
= 2.27m
