Explanation:
Tension in the rope
[tex]\begin{aligned}T_{1} &=0.4 \times x \\T_{2} &=100+0.4 \times 10 \\&=104\end{aligned}[/tex]
[tex]M s=0.3[/tex] ∅ [tex]=2 \cdot 5(2 \pi)=5 \pi[/tex]
[tex]\begin{aligned}\frac{T_{1}}{T_{2}}=e^{\mu \theta} & \Rightarrow \frac{104}{0.4 x}=e^{0.3(5 \pi)} \\& \Rightarrow x=2.34 \mathrm{H}\end{aligned}[/tex]
NOTE : Refer the image
