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uppose the genes for eye color and wing shape are both on the X chromosome (they are linked) and are known to be 68 map units apart. In a mating between a Xw+m+Xwm female and a XwmY male that produces 1000 progeny, how many recombinant progeny would you expect to observe?

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Oseni

Answer:

680 recombinant progeny

Explanation:

Since the two genes are 68 map units apart on the same chromosome, it simply means that the frequency of recombination is 60 percent. Hence, recombinant offspring will be 60 percent of the total number of offspring produced.

Since the total number of progeny is 1000,

Number of recombinant progeny = 68/100 x 1000

                    = 680 progeny.

680 recombinant progeny are expected to be observed.

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