The total amount of heat absorbed by the water is 4079.4 J
We'll begin by calculating the the change in the temperature of the water.
- Initial temperature of water (T₁) = 25 °C
- Final temperature (T₂) = 40 °C
- Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 40 – 25
ΔT = 15 °C
Finally, we shall determine the heat absorbed by the water.
- Mass of water (M) = 65 g
- Change in temperature (ΔT) = 15 °C
- Specific heat capacity of water (C) = 4.184 J/gºC
- Heat absorbed (Q) =?
Q = MCΔT
Q = 65 × 4.184 × 15
Q = 4079.4 J
Therefore, the amount of heat absorbed by the water is 4079.4 J
Learn more about heat transfer: https://brainly.com/question/25809522
