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4.80-kg bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 75.0 N. If the bucket starts from rest, what is the minimum time required to raise the bucket a vertical distance of 12.0 m without breaking the cord?

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anniwuanyanwu1

Answer:

Time,t=2.03seconds

Explanation:

Fg= 4.80×9.80= 47.04N

Maximum accelerating force= 75-47.04=27.96N

F= ma

27.96= 4.80 ×a

27.96/4.80=a

5.825m/s^2 =a

d=1/2at^2

d=12.0m

12=1/2 × 5.825 ×t^2

12 =2.913×t^2

t^2= 12/2.913

t= sqrt(4.120)

t= 2.03seconds

Explanation:

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