[tex]x=\sqrt{70}, y =\sqrt{21}, z=\sqrt{30}[/tex]
Solution:
Given c = 3 and d = 10 – 3 = 7
To find the value of y:
[tex]y^2= 3\times 7[/tex]
[tex]y^2= 21[/tex]
Taking square root on both sides of the equation.
[tex]y=\sqrt{21}[/tex]
To find the value of x:
[tex]x^2=7\times10[/tex]
[tex]x^2=70[/tex]
Taking square root on both sides of the equation.
[tex]x=\sqrt{70}[/tex]
To find the value of z:
[tex]z^2=3\times10[/tex]
[tex]z^2=30[/tex]
Taking square root on both sides of the equation.
[tex]z=\sqrt{30}[/tex]
Hence the value of [tex]x=\sqrt{70}, y =\sqrt{21}, z=\sqrt{30}[/tex].
