Answer:
The binomial distribution, with parameters n = 5 and p = 0.7
Step-by-step explanation:
For each card observed, there are only two possible outcomes. Either it is a name corresponding to a male student, or it is a name corresponding to a female student. Since the cards are replaced, that is, place back in the set, the propability of taking a male student is each obervation is independent from other observations. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
This is done a total of five times.
Which means that [tex]n = 5[/tex]
Let X be the number of cards observed in these five trials with a name corresponding to a male student.
Each trial, there is a 7/10 probability of observing a male student. So
[tex]p = \frac{7}{10} = 0.7[/tex]
So the correct answer is:
The binomial distribution, with parameters n = 5 and p = 0.7
Answer:
last one. B(5,0.7)
Step-by-step explanation:
Since no. of times getting a Male is discrete and probability of success is constant, it will follow a binomial distribution.
Let X be the no. of males
Then X ~ B(5, 0.7)
Where 5 is the no. of trials and 0.7 is the probability of success
Success is getting a Male.
So probability of success = 7/10 =0.7
