Answer:
F=264.045 N
Explanation:
Initial speed u = 0
Final speed v = 304 m/s
Distance covered S = 0.77 m
Mass of the bullet m = 4.4 g = 4.4 x 10⁻³ Kg
Acceleration of the bullet a
[tex]a=\dfrac{v^2-u^2}{2S}[/tex]
[tex]a=\dfrac{304^2-0^2}{2\times 0.77}\ m/s^2[/tex]
a=60010.38 m/s²
Force applied on the bullet F = ma
F=4.4 x 10⁻³ x 60010.38 N
F=264.045 N
