Answer 1:
The input power into the mother is 1.1 kW
The output power at the shaft is = 1.068 kW
Explanation:
Electrical power = input = Volt*current = 10*110 = 1100W = 1.1kW
Motor shaft power = output = Torque*angular speed
Angular speed = 2¶N/60 = (2*3.142*1000)/60 = 104.4 rad/sec
Ouput = 10.2*104.4 =1068W = 1.068kW
Answer 2: net power input = 0.032kW
Explanation: net power input = power input-power output.
Answer 3: energy transfered into the motor = 1100J in one sec
Energy transfer to shaft is 1068J in one sec
Explanation: power is energy expended per unit sec.
a) Electric power = 1.2kW and output = 1.068kW
b) Net power input = 0.032kW
c) The amount of energy transferred to the motor by electrical work = 1100J
Electric power is the rate work is done, or the rate at which energy is consumed or produced.
In terms of current and voltage it is given by:
[tex]\text{Power}=\text{Current}*\text{Volatge}[/tex].........(i)
a)
Given:
The input power into the mother = 1.1 kW
The output power at the shaft is = 1.068 kW
To find:
Electrical power=?
On substituting the values in equation (i)
Electrical power= Input
[tex]\text{Electrical power} =\text{Volt} * \text{Current} \\\\\text{Electrical power}= 10*110 = 1100W \\\\\text{Electrical power}= 1.1kW[/tex]
Output = Torque * Angular speed
Angular speed= (2 π N)/ (60)
Angular speed = (2*3.142*1000) / (60)
Angular speed =104.4 rad/sec
Output = 10.2*104.4 =1068W = 1.068kW
b)
Net power input = 0.032kW
Net power input = power input-power output.
c)
Energy transferred into the motor = 1100J in one sec
Energy transfer to shaft is 1068J in one sec
Power is energy expended per unit sec.
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