Answer:
The efficiency of the engine is 9.3%
Explanation:
Efficiency = power output/power input × 100
Power output = 50 kW
Power input = heating value × density × volumetric flow rate
Heating value = 44,000 kJ/kg
Density = 2 g/cm^3 = 2/1000 = 0.002 kg/cm^3
Volumetric flow rate = 22 L/hr = 22 L/hr × 1000 cm^3/1 L × 1 hr/3600 s = 6.11 cm^3/s
Power input = 44,000 kJ/kg × 0.002 kg/cm^3 × 6.11 cm^3/s = 537.68 kJ/s = 537.68 kW
Efficiency = 50 kW/537.68 kW × 100 = 9.3%
