Answer: The mass of sulfur trixoide is 0.0485 g
Explanation:
We are given:
Molecules of sulfur trixoide = [tex]3.65\times 10^{20}[/tex]
According to mole concept:
[tex]6.022\times 10^{23}[/tex] number of molecules are present in 1 mole of a compound
So, [tex]3.65\times 10^{20}[/tex] number of molecules will be present in = [tex]\frac{1}{6.022\times 10^{23}}\times 3.65\times 10^{20}=6.06\times 10^{-4}mol[/tex]
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Moles of sulfur trixoide = [tex]6.06\times 10^{-4}mol[/tex]
Molar mass of sulfur trioxide = 80 g/mol
Putting values in above equation, we get:
[tex]6.06\times 10^{-4}mol=\frac{\text{Mass of }SO_3}{80g/mol}\\\\\text{Mass of }SO_3=(6.06\times 10^{-4}mol\times 80g/mol)=0.0485g[/tex]
Hence, the mass of sulfur trixoide is 0.0485 g