Answer:
33705 N
Explanation:
We are given that
Mass of cabin=550 kg
Maximum load=2600 kg
Total mass,m=550+2600=3150 kg
Initial velocity=u=0
Final velocity=v=2.7 m/s
Time=3 s
We have to fine the tension of the elevator rope to withstand.
Acceleration=[tex]\frac{v-u}{t}=\frac{2.7}{3}=0.9m/s^2[/tex]
Net force=[tex]F_{net}=T-mg[/tex]
[tex]ma=T-mg[/tex]
[tex]T=ma+mg=m(a+g)[/tex]
Where [tex]g=9.8m/s^2[/tex]
Using the formula
[tex]T=3150(0.9+9.8)[/tex]
[tex]T=33705 N[/tex]
