The partial pressure of carbon dioxide in a gas mixture is 3.5 atm. What will be the solubility (in M) of carbon dioxide gas when Henry's Law constant for carbon dioxide is 3.4 x 10-2M/atm

Respuesta :

Answer: The solubility of carbon dioxide gas is 0.119 M

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

[tex]C_{CO_2}=K_H\times p_{CO_2}[/tex]

where,

[tex]K_H[/tex] = Henry's constant = [tex]3.4\times 10^{-2}mol/L.atm[/tex]

[tex]p_{CO_2}[/tex] = partial pressure of carbon dioxide gas = 3.5 atm

Putting values in above equation, we get:

[tex]C_{CO_2}=3.4\times 10^{-2}mol/L.atm\times 3.5atm\\\\C_{CO_2}=0.119M[/tex]

Hence, the solubility of carbon dioxide gas is 0.119 M

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