Respuesta :
Answer:
In 12 s, atom goes 17.592 m distance.
(a) Speed of the atom is 8.796 m/s.
(b) The direction of the velocity of this atom is tangent to the circle.
Explanation:
Let r be the radius of the circular path and v be the speed of the atom in the outer rim.
Circumference of the circular path, d = 2πr
Substitute 14 m for r in the above equation.
Circumference of the circular path, d = 2 x π x 14 = 87.96 m
According to the problem, atom completes a revolution in 10 seconds. So, atom covers 87.96 m in 10 seconds.
Distance covered by atom in 1 second = [tex]\frac{87.96}{10}[/tex] = 8.796 m
Since, atom come back to its initial position after 10 seconds, so displacement of atom is zero. Hence,
Distance covered by atom in 12 seconds = 8.796 x 2 = 17.592 m
(a) Speed of the atom is determine by the relation :
v = [tex]\frac{distance}{time}[/tex] = [tex]\frac{87.96}{10}[/tex]
v = 8.796 m/s
(b) In circular motion, the direction of the velocity of the atom is tangent to the the circle.
The distance traveled by the atom in 12s is 105.5m
(a) speed of the atom is 8.792 m/s
(b) the direction of the velocity is tangential to the circular path.
Circular motion:
It is given that the time period to complete one revolution is T = 10s. This means the atom will travel a distance equal to the circumference in 10 seconds.
Circumfrence = 2πr = 2×3.12×14m = 87.92m in 10 seconds.
So in 12 seconds, the atom travels a distance = [tex]\frac{87.92\times12}{10}=105.5\;m[/tex]
(a) The speed of the atom
[tex]speed =\frac{distance }{time}\\\\speed =\frac{87.92}{10}\;m/s\\\\speed=8.792\;m/s[/tex]
(b) The direction of the velocity of the atom will be tangential to the circular path of the motion.
Learn more about circular motion:
https://brainly.com/question/118814?referrer=searchResults
