Respuesta :
Answer:
We need to add 51.52 grams of sucrose
Explanation:
Step 1: Data given
Mass of water = 488 grams
Density = 1g/mL
osmotic pressure = 8.00 atm
Temperature = 290 K
Step 2: Calculate concentration
π = i*M*R*T
8.00 atm = 1* M*0.08206 * 290
M = 0.336 M
Step 3: Calculate volume of water
488 grams = 0.488 L
Step 4: Calculate moles sucrose
moles sucrose = molarity * volume
Moles sucrose = 0.336 M * 0.448 L
Moles sucrose = 0.1505 moles
Step 5: Calculate mass sucrose
Mass sucrose = 0.1505 moles * 342.3 g/mol
Mass sucrose = 51.52 grams
We need to add 51.52 grams of sucrose
The mass of sucrose will be 51.52 grams .
Given:
Mass of water = 488 grams
Density = 1g/mL
Osmotic pressure = 8.00 atm
Temperature = 290 K
Calculation for Concentration:
[tex]\pi = i*M*R*T\\\\8.00 atm = 1* M*0.08206 * 290\\\\M = 0.336 M[/tex]
Conversion for Volume:
488 grams = 0.488 L
Calculation for number of moles:
[tex]\text{ Moles of sucrose} = Molarity * Volume\\\\\text{ Moles of sucrose} = 0.336 M * 0.448 L\\\\\text{ Moles of sucrose} = 0.1505 moles[/tex]
Calculation for Mass:
[tex]\text{Mass of sucrose} = 0.1505 moles * 342.3 g/mol\\\\\text{Mass of sucrose} = 51.52 grams[/tex]
Thus, the mass of sucrose will be 51.52 grams.
Find more information about Moles here:
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