Answer:
E. Approximately normal with standard deviation less than 0.7 sibling
Step-by-step explanation:
To solve this question, we use the Central Limit theorem.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, we have that:
Skewed right distribution, with [tex]\mu = 1.8, \sigma = 0.7[/tex]
Sampling distribution of the sample mean for samples of size 100
By the Central Limit Theorem, they will be approximately normal, with mean [tex]\mu = 1.8[/tex], and standard deviation [tex]s = \frac{0.7}{\sqrt{100}} = 0.07[/tex]
So the correct answer is:
E. Approximately normal with standard deviation less than 0.7 sibling