Answer:
The value of the test statistic is -1.539 .
Step-by-step explanation:
We are given with the following hypothesis test ;
[tex]H_0[/tex] : [tex]\mu[/tex] = 18
[tex]H_1[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 18
Also, we are provided a Sample mean, [tex]Xbar[/tex] = 17 and a Sample standard deviation, s = 4.5.
The test statistics we will use here is;
[tex]\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
So, test statistics = [tex]\frac{17-18}{\frac{4.5}{\sqrt{48} } }[/tex] ~ [tex]t_4_7[/tex] { as n = sample size = 48 }
= -1.539 .
Therefore, the value of the test statistic is -1.539 .
