Answer:
(A). The average tangential acceleration of the top of the racket is 200 m/s².
(B). The magnitude of the rotational acceleration of your arm and racket is 133.3 rad/s²
Explanation:
Given that,
Speed = 20 m/s
Time = 0.10 sec
Distance r= 1.5 m
(A). We need to calculate the average tangential acceleration of the top of the racket
Using equation of motion
[tex]v=u+at[/tex]
Here, u =0
[tex]v = at[/tex]
[tex]a=\dfrac{v}{t}[/tex]
Put the value into the formula
[tex]a=\dfrac{20}{0.10}[/tex]
[tex]a=200\ m/s^2[/tex]
The average tangential acceleration of the top of the racket is 200 m/s².
(B). We need to calculate the magnitude of the rotational acceleration of your arm and racket
Using formula of rotational acceleration
[tex]\alpha=\dfrac{a_{t}}{r}[/tex]
Put the value into the formula
[tex]\alpha=\dfrac{200}{1.5}[/tex]
[tex]\alpha=133.33\ rad/s^2[/tex]
The magnitude of the rotational acceleration of your arm and racket is 133.3 rad/s²
Hence, (A). The average tangential acceleration of the top of the racket is 200 m/s².
(B). The magnitude of the rotational acceleration of your arm and racket is 133.3 rad/s²
The magnitude of the average tangential acceleration is 200 m/s².
The magnitude of the rotational acceleration of your arm is 133.33 rad/s².
The given parameters;
The magnitude of the average tangential acceleration is calculated as follows;
[tex]a = \frac{v}{t} \\\\\ a = \frac{20}{0.1} \\\\ a = 200 \ m/s^2[/tex]
The magnitude of the rotational acceleration of your arm is calculated as
[tex]a_r = \frac{a_t}{r} \\\\a_r = \frac{200}{1.5} \\\\a_r = 133.33 \ rad/s^2[/tex]
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