Option A:
[tex](x-5)^{2}+(y-3)^{2}=16[/tex]
Solution:
Given data:
Center of the circle is (5, 3).
Radius of the circle = 4
To find the equation of the circle:
The general form of the equation of a circle in centre-radius format is
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where (h, k) is the centre of the circle and r is the radius of the circle.
Substitute the given values in the equation of a circle formula:
[tex](x-5)^{2}+(y-3)^{2}=4^{2}[/tex]
[tex](x-5)^{2}+(y-3)^{2}=16[/tex]
The equation of the given circle is [tex](x-5)^{2}+(y-3)^{2}=16[/tex].
Hence Option A is the correct answer.
