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Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 18 N, 6.0 N, 9.0 N, and 12 N, and you do 36 J of work on each. Match each box to the vertical distance through which it is lifted. 2.0 m

Respuesta :

Explanation:

It is known that the relation between work and force is as follows.

              w = [tex]F \times d cos (\theta)[/tex]

where,    [tex]\theta[/tex] = angle between the applied force and direction of movement of the object which is zero in this case. As, cos (0) = 1.

Therefore,    d = [tex]\frac{w}{F}[/tex]

(i)   For w = 36 J, and F = 9 N then value of d will be as follows.

                    d = [tex]\frac{w}{F}[/tex]

                       = [tex]\frac{36 J}{9 N}[/tex]

                       = 4 m

(ii)  For w = 36 J, and F = 12 N then value of d will be as follows.

                    d = [tex]\frac{w}{F}[/tex]

                       = [tex]\frac{36 J}{12 N}[/tex]

                       = 3 m

(iii)  For w = 36 J, and F = 6 N then value of d will be as follows.

                    d = [tex]\frac{w}{F}[/tex]

                       = [tex]\frac{36 J}{6 N}[/tex]

                       = 6 m

(iv)  For w = 36 J, and F = 18 N then value of d will be as follows.

                    d = [tex]\frac{w}{F}[/tex]

                       = [tex]\frac{36 J}{18 N}[/tex]

                       = 2 m

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