Answer:
[tex]C_2H_6N[/tex]
Explanation:
Hello,
In this case, considering the given percentages, we compute the mole ratios as shown below:
[tex]n_C=\frac{0.545}{12}=0.0454\\n_H=\frac{0.1373}{1}=0.1373\\n_N=\frac{0.3177}{14}=0.0227[/tex]
Now, by dividing all the mole ratios by the smallest ratio, we obtain the subscripts for the required empirical formula as shown below:
[tex]C=\frac{0.0454}{0.0227} =2\\H=\frac{0.1373}{0.0227}=6\\N=\frac{0.0227}{0.0227}=1[/tex]
Therefore, the empirical formula turns out:
[tex]C_2H_6N[/tex]
Best regards.
