Answer:
17.2 minutes is the value of the turnover number.
Explanation:
Using Michaelis-Menten equation:
[tex]V = V_{max}\times \frac{[S]}{ (Km + [S])}[/tex]
[tex]V_{max }=k_{cat}\times E_o[/tex]
Where :
[tex]V_{max}[/tex] = max rate velocity
[S] = substrate concentration
[tex]K_m[/tex] = Michaelis-Menten constant
V = reaction rate
[tex]k_{cat}[/tex] = catalytic rate constant
[tex]E_o[/tex] = initial enzyme concentration
We have :
[tex]K_m=10.0mM[/tex]
[tex]E_o=10.0\mu M=10.0\times 0.001 mM[/tex]
[tex]V_{max}=0.172 mM/min[/tex]
[tex]V_{max}[/tex] is the rate is obtained when all enzyme is bonded to the substrate. [tex]k_{cat}[/tex] is termed as the turnover number.
[tex]k_{cat}=\frac{V_{max}}{E_o}=\frac{0.172 mM}{10.0\times 0.001 mM}[/tex]
[tex]=17.2 minutes[/tex]
17.2 minutes is the value of the turnover number.
