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In ΔBCD, the measure of ∠D=90°, the measure of ∠C=77°, and CD = 41 feet. Find the length of BC to the nearest foot.
(SOMEONE GIVE ME AN ACCURATE ANSWER PLEASE
*IM STRESSING OUT OVER THIS AND NOBODY IS HELPING OUT*
THIS IS QUESTION #2 AND I HAVE LIKE 15)

Respuesta :

amna04352

Answer:

182 ft

Step-by-step explanation:

BDC is a right angle triangle.

With respect to angle C, CD is the adjacent length and BC is the hypotenuse.

cos(C) = adjacent/hypotenuse

cos(77) = 41/BC

BC = 41/cos(77)

BC = 182.261870786

BC = 182

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