Given: v is constant at any value and x=50 m, then find the maximum hieght which is [tex]y_{max}[/tex]. We can also see that the motion of horizontal direction is given by [tex]x=v_{x}t[/tex], and also, since [tex]v_{x}=v_{i}[/tex] it's [tex]v_{i}t=50[/tex], also [tex]t_{1}=\frac{t}{2}[/tex]. So now just put this in the equation [tex]y_{max}=v_{yi}+\frac{1}{2}gt^{2}_{1}[/tex] you will get ymax being 12.6 along with using the equation [tex]v_{yf}=v_{yi}-gt_{1}[/tex].
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)
- Cutiepatutie ☺❀❤
