The rotating cow is attached to the pivot by a string, thus its motion requires a definite period. The period of rotation of the cow is 1.85 s.
The period of rotation of an object is the time that would be required for the object to complete one cycle or revolution.
Thus from the given diagram, let the length of the string holding the cow to the pivot be represented by x. So that applying the Pythagoras theorem, we have:
[tex]Hyp^{2}[/tex] = [tex]Adj 1^{2}[/tex] + [tex]Adj 2^{2}[/tex]
[tex]x^{2}[/tex] = [tex]75^{2}[/tex] + [tex]40^{2}[/tex]
= 7225
x = [tex]\sqrt{7225}[/tex]
= 85
Thus , the length of the string is 85 cm.
So that, the period of rotation of the cow can be determined as follows:
Period, T = 2[tex]\pi[/tex][tex]\sqrt{\frac{l}{g} }[/tex]
where l is the length of the string and g is the gravitational force.
l = x = 85 cm (0.85 m), g = 9.8 m/[tex]s^{2}[/tex]
Therefore,
T = 2 x [tex]\frac{22}{7}[/tex] x [tex]\sqrt{\frac{0.85}{9.8} }[/tex]
= [tex]\frac{44}{7}[/tex] x 0.29451
= 1.85121
T = 1.85 s
See more about Period of rotation at: https://brainly.com/question/20424005
