Change in kinetic energy compared to a 100 kg ball travelling at 5 m/s
A 1,000 kg ball traveling at 5 m/s - 11250 J
A 10 kg ball traveling at 5 m/s- 1125 J
A 100 kg person falling at 5 m/s - 0 J
Explanation:
We have to initially calculate the kinetic energy of a 100 kg ball travelling at 5m/s.
[tex]k=1/2 mv^2\\=1/2 \times 100 \times 5^2\\=1250J[/tex]
calculating the kinetic energy of a 1000 kg ball travelling at 5 m/s
[tex]k=1/2 mv^2\\1/2 \times 1000\times 5^2\\=12500 J[/tex]
difference in kinetic energy=12500-1250=11250 J
calculating the energy of 10 kg ball travelling at 5 m/s
[tex]k=1/2 mv^2\\=1/2 \times 10 \times 5^2\\=125 J[/tex]
difference in kinetic energy=1250-125=1125 J
calculating the kinetic energy of a 100 kg person falling at 5 m/s
[tex]k=1/2 mv^2\\=1/2 \times 100\times 5^2\\=1250 J[/tex]
difference in kinetic energy=1250-1250=0 J
Answer:
A 1,000 kg ball traveling at 5 m/s would have 10 times more
kinetic energy
A 10 kg ball traveling at 5 m/s would have 10 times less
kinetic energy
A 100 kg person falling at 5 m/s would have The Same
kinetic energy.
Explanation:
I hope that this helps!!!
