In ΔBCD, the measure of ∠D=90°, the measure of ∠C=77°, and CD = 41 feet. Find the length of BC to the nearest foot.

In ΔBCD the measure of D90 the measure of C77 and CD 41 feet Find the length of BC to the nearest foot class=

Respuesta :

Answer: [tex]x\approx182\ ft[/tex]

Step-by-step explanation:

For this exercise you need to use the following Trigonometric Identity:

[tex]cos\alpha =\frac{adjacent}{hypotenuse}[/tex]

Observe the Right triangle BCD given in the exercise. You can identify that, in this case:

[tex]\alpha =\angle C=77\°\\\\adjacent=CD=41\ ft\\\\hypotenuse=BC=x[/tex]

Knowing these values, you can substitute them into  [tex]cos\alpha =\frac{adjacent}{hypotenuse}[/tex], as below:

 [tex]cos(77\°)=\frac{41}{BC}[/tex]

The next step is to solve for "x" in order to find its value:

[tex]x*cos(77\°)=41\\\\x=\frac{41}{cos(77\°)}\\\\x=182.26\ ft[/tex]

Finally, rounded the result to the nearest foot, you get that this is:

[tex]x\approx182\ ft[/tex]

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