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If a balloon containing 1,200 L of gas at 25°C and 760 mmHg pressure ascends to an altitude where the pressure is 380 mmHg and the temperature is 54°C, the volume will be: (Be sure to use the correct number of significant figures.) 3.8 x 10 -4 L 2,200 L 660 L 2,600 L

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Answer:

The volume will be 2600 L.

Explanation:

Initial temperature ([tex]T_{1}[/tex]) = 25°C = (25 + 273) K = 298K

Final temperature ([tex]T_{2}[/tex]) = 54°C = (54 + 273) K = 327 K

By using the combined gas law equation,

                                 [tex]\frac{P_{1} V_{1} }{T_{1} }[/tex] = [tex]\frac{P_{2} V_{2} }{T_{2} }[/tex]

                       or, [tex]\frac{760* 1200}{298}[/tex] = [tex]\frac{380* V_{2} }{327}[/tex]

                      or, 3060 × 327 = 380 × [tex]V_{2}[/tex]

                      or, [tex]V_{2}[/tex] ≈ 2600 L

Hence the volume of the balloon will be about 2600 L.

Answer:

2,600

Explanation:

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