Answer:
The volume will be 2600 L.
Explanation:
Initial temperature ([tex]T_{1}[/tex]) = 25°C = (25 + 273) K = 298K
Final temperature ([tex]T_{2}[/tex]) = 54°C = (54 + 273) K = 327 K
By using the combined gas law equation,
[tex]\frac{P_{1} V_{1} }{T_{1} }[/tex] = [tex]\frac{P_{2} V_{2} }{T_{2} }[/tex]
or, [tex]\frac{760* 1200}{298}[/tex] = [tex]\frac{380* V_{2} }{327}[/tex]
or, 3060 × 327 = 380 × [tex]V_{2}[/tex]
or, [tex]V_{2}[/tex] ≈ 2600 L
Hence the volume of the balloon will be about 2600 L.