Answer:
d= 0.48 m
Explanation:
Given that
time ,t= 40 m s= 40 x 10⁻³ s
Constant acceleration ,a= - 60 g
We know that g= 10 m/s²
Therefore ,a=- 60 x 10 =- 600 m/s²
We know that
v= u + a t
u=initial speed
v=final sped
t=time
a=acceleration
Now by putting the value
0 = u - 600 x 40 x 10⁻³
u = 24 m/s
The distance cover before coming to stop d is given as
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
[tex]d=24\times 40\times 10^{-3}-\dfrac{1}{2}\times 600\times (40\times 10^{-3})^2[/tex]
d= 0.48 m
