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Two parakeets sit on a swing with their combined center of mass 10.0 cm below the pivot. At what frequency do they swing?

Respuesta :

Hashirriaz830

Answer:

1.58 Hz

Explanation:

The frequency of the simple pendulum is given by

f = 1/T

 = 1/2π√g/l  

In this problem, I = 10.0 cm = 0.1 m  

f = 1/2π√9.8/0.1

=  1.58 Hz

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