Answer:
Probability = 0.0788
Step-by-step explanation:
Mikayla buys a bag containing,
Sugar cookies = 8
Oatmeal cookies = 9
Chocolate cookies = 8
Peanut cookies = 4
Total number of cookies in the bag = 8 + 9 + 8 + 4 = 29
Probability that Mikayla randomly selects a chocolate chip cookie
= [tex]\frac{\text{total number of chocolate cookies}}{\text{Number of cookies in the bag}}[/tex]
= [tex]\frac{8}{29}[/tex]
Now number of cookies left in the bag = 29 - 1 = 28
She eats it then randomly selects another cookie.
Probability that the selected cookie will be a sugar cookie
= [tex]\frac{\text{total number of sugar cookies}}{\text{Number of cookies left in the bag}}[/tex]
= [tex]\frac{8}{28}[/tex]
= [tex]\frac{2}{7}[/tex]
Now probability of occurrence of both the events = [tex]\frac{8}{29}\times \frac{2}{7}[/tex]
= [tex]\frac{16}{203}[/tex]
= 0.0788
The probability to select the chocolate chip cookie is 8/29 and probability to select the sugar cookie is 8/28.
Given data:
Number of chocolate chip cookies in a bag is, 8.
Number of peanut butter cookies is, 4.
Number of sugar cookies is, 8.
The number of oatmeal cookies is, 9.
The problem uses the concept of probability which is defined as the ratio of possible outcome to the total number of outcomes in a sample space.
Total number of cookies in bag is, 8 + 4 + 8 + 9 = 29.
So, the probability that Mikayla randomly selects a chocolate chip cookie from the bag is,
[tex]p= \dfrac{8}{29}[/tex]
Now, the number of cookies left in the bag is, 29 -1 = 28.
So, to select the sugar cookie from the 28 remaining cookies, the required probability is,
[tex]p'=\dfrac{8}{28}[/tex]
Thus, we can conclude that the probability to select the chocolate chip cookie is 8/29 and probability to select the sugar cookie is 8/28.
Learn more about the probability here:
https://brainly.com/question/11234923
