Answer:
The probability that the page will get at least one hit during any given minute is 0.9093.
Step-by-step explanation:
Let X = number of hits a web page receives per minute.
The random variable X follows a Poisson distribution with parameter,
λ = 2.4.
The probability function of a Poisson distribution is:
[tex]P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...[/tex]
Compute the probability that the page will get at least one hit during any given minute as follows:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)
[tex]=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093[/tex]
Thus, the probability that the page will get at least one hit during any given minute is 0.9093.
