Answer: y = 2.4×10^-6m or y= 2.4μm
Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as
y = R×mλ/d
Where y = distance between nth fringe and Central bright spot fringe.
m = position of fringe = 4
λ = wavelength of light= 600nm = 600×10^-9 m
d = distance between slits = 1.50×10^-5m
R = distance between slit and screen = 2m
y = 2 × 4 × 600×10^-9/2
y = 4800×10^-9/2
y = 2400 × 10^-9
y = 2.4×10^-6m or y= 2.4μm
The distance on the screen between the central bright fringe and the fourth-order bright fringe is [tex]2.6 \times 10^{-6} \;\rm m[/tex].
Given data:
The distance between the two slits is, [tex]d =1.50 \times 10^{-5} \;\rm m[/tex].
The wavelength of coherent light is, [tex]\lambda =600 \;\rm nm =600 \times 10^{-9} \;\rm m[/tex].
The distance between the slit and screen is, R = 2.00 m.
The formulae for the distance between the central bright fringe to any other fringe in pattern is given as
y = R×mλ/d
Here,
m is the order of fringes formed. And it is also used for representing the position of image, and for fourth-order bright fringe, m = 4.
Solve by substituting the values as,
[tex]y = \dfrac{2 \times 4 \times 600 \times 10^{-9}}{1.50 \times 10^{-5}}\\\\y =2.6 \times 10^{-6} \;\rm m[/tex]
Thus, we can conclude that the distance on the screen between the central bright fringe and the fourth-order bright fringe is [tex]2.6 \times 10^{-6} \;\rm m[/tex].
Learn more about the central bright fringe here:
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